
1 Report for Oveta Swanson
Find the right Oveta Swanson by their age, location, and contact info below
Lives in:
124 Ranger Pl, Slidell, LA
Emails:
m*****@hotmail.com
May be related to:
+1 more- Phone Numbers (4)
- Addresses (3)
- Email Addresses (1)
- Social Profiles (0)
- Relatives (6)
Oveta Swanson Summary
1 individuals identified as Oveta Swanson were located throughout the United States across all 50 states. Predominantly, they reside in New Orleans, LA, with subsequent concentrations in Slidell, LA. Public records indicate that the ages of these individuals span from 84 to 84 years old. Some possible relatives include Cynthia Swanson, Lester Swanson, and Daniel Swanson. Additionally, our search revealed a collective total of 6 phone numbers associated with Oveta Swanson, one of which is (985) 259-0375. 985, 504 are some of the most popular area codes for these people.Oveta Swanson in Numbers
Statistics based on the US Census data for all 1 people with this name.Single vs. Married
- Married100%
- Single0%
Alive vs. Deceased
- Deceased17%
- Alive83%
- <25k
- 25-50k
- 50-75k
- 75-100k
- 100-125k
- 125-150k
- 150-200k
- 200k+
- 18%
- 20.9%
- 18.6%
- 14.1%
- 10.4%
- 8.4%
- 10.8%
- 13.6%
The average income for Oveta Swanson is 65k
- Gmail
- Yahoo
- Outlook
- AOL
- Other
- 63%
- 11%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
54
Average Age
- 0-1823%
- 18-259%
- 25-3514%
- 35-4513%
- 45-5512%
- 55-6513%
- 65-8515%
- 85+2%
Oveta Swanson F.A.Q.
Discover our primary finding for Oveta Swanson in under 60 seconds!
How old is Oveta Swanson?
Oveta Swanson is 84 years old.
What is Oveta Swanson's last known address?
124 Ranger Pl, Slidell, LA, 70458
What is Oveta Swanson's last contact number?
Oveta Swanson's phone number is (985) 259-0375.
What is Oveta Swanson's email address?
m*****@hotmail.com
Is Oveta Swanson married?
100% of people matching the name Oveta Swanson are married.
Does Oveta Swanson have a criminal record?
No criminal records found matching the name Oveta Swanson.