Lives in:
2646 5th Street Rd, Huntington, WV
Used to live in:
106 Township Road 1041, Chesapeake, OH •
3711 Squires Mill Rd, Joliet, IL •
1002 Celebration Dr, Aurora, IL •
+2 morePhone number(s):
(815) 782-4458
- Addresses (5)
- Phone Numbers (1)
- Social Profiles (0)
- Email Addresses (0)
- Relatives (4)
Jai Danford Summary
1 individuals identified as Jai Danford were located throughout the United States across all 50 states. Predominantly, they reside in Illinois, with subsequent concentrations in Ohio and West Virginia. Public records indicate that the ages of these individuals span from Infinity to -Infinity years old. Some possible relatives include Barbara Danford, Nick Danford, and Seneca Danford. Additionally, our search revealed a collective total of 1 phone numbers associated with Jai Danford, one of which is (815) 782-4458. 815 are some of the most popular area codes for these people.Jai Danford in Numbers
Statistics based on the US Census data for all 1 people with this name.- Single100%
- Married0%
- Deceased17%
- Alive83%
- <25k
- 25-50k
- 50-75k
- 75-100k
- 100-125k
- 125-150k
- 150-200k
- 200k+
- 25.9%
- 30.1%
- 26.8%
- 20.3%
- 15%
- 12.1%
- 15.5%
- 19.7%
The average income for Jai Danford is 45k
- Yahoo
- Gmail
- Outlook
- AOL
- Other
- 11%
- 63%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
We are always updating our data. Please check back later for results.
Caucasian
Major Ethnicity
- Caucasian100%
- Other/Undisclosed0%
Jai Danford F.A.Q.
Discover our primary finding for Jai Danford in under 60 seconds!
How old is Jai Danford?
Age is just a number.
What is Jai Danford’s last known address?
2646 5th Street Rd, Huntington, WV, 25701
What is Jai Danford’s last contact number?
Jai Danford’s phone number is (815) 782-4458.
What is Jai Danford’s email address?
No email address found.
Is Jai Danford married?
No marriage records found matching the name Jai Danford.
Does Jai Danford have a criminal record?
No criminal records found matching the name Jai Danford.