
1 Report for Annita Waddell
Find the right Annita Waddell by their age, location, and contact info below
Lives in:
204 Robinhood Rd, Hartsville, SC
Used to live in:
1230 Basin Rock Ln, # 38, Lexington, SC •
Po Box 7162, West Columbia, SC •
6045 Whispering Lakes Dr, Katy, TX •
1549 Glendale Rd, Columbia, SC •
+1 moreMay be related to:
+1 more- Phone Numbers (6)
- Addresses (5)
- Email Addresses (14)
- Social Profiles (143)
- Relatives (6)
Annita Waddell Summary
1 individuals identified as Annita Waddell were located throughout the United States across all 50 states. Predominantly, they reside in South Carolina, with subsequent concentrations in Texas. Public records indicate that the ages of these individuals span from 70 to 70 years old. Some possible relatives include Creo Waddell, Kenneth Waddell, and Christina Waddell. The most prevalent area codes associated with Annita Waddell include 803, 405, 561. Public records show 20 emails are associated with Annita Waddell.Annita Waddell in Numbers
Statistics based on the US Census data for all 1 people with this name.We are always updating our data. Please check back later for results.
Alive vs. Deceased
- Deceased17%
- Alive83%
We are always updating our data. Please check back later for results.
- Gmail
- Yahoo
- Outlook
- AOL
- Other
- 63%
- 11%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
We are always updating our data. Please check back later for results.
Annita Waddell F.A.Q.
Discover our primary finding for Annita Waddell in under 60 seconds!
How old is Annita Waddell?
Annita Waddell is 70 years old.
What is Annita Waddell's last known address?
204 Robinhood Rd, Hartsville, SC, 29550
What is Annita Waddell's last contact number?
Annita Waddell's phone number is (803) 920-6897.
What is Annita Waddell's email address?
h*****@yahoo.com
Is Annita Waddell married?
No marriage records found matching the name Annita Waddell.
Does Annita Waddell have a criminal record?
No criminal records found matching the name Annita Waddell.